Dategrain combined with aggregation

enara_martin · 2022-05-04T18:42:06+00:00

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As I can read here: https://developer.domo.com/docs/dev-studio-references/data-api#aggregations

"DATEGRAIN

Perform a groupby with predefined date grains. By default, numerical columns are summed and unique entries of non-numerical columns are counted. Can be combined with an aggregation to override this default behavior."

I would like to change the default sum to an average. How could this be changed?

My query looks like this:

var dataAggregateBy = 'day';
var dategrain = [dataDateColumnName + ' by ' + dataAggregateBy];
var query = `/data/v1/${datasets[0]}?fields=${fields.join()}&dategrain=${dategrain.join()}&filter=${filter.join()}`;

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Accepted answers

GrantSmith

According to that documentation you should be able to supply it as a GET parameter with the value of a cvs list of fields you wish you average:

var dataAggregateBy = 'day';
var dategrain = [dataDateColumnName + ' by ' + dataAggregateBy];
var query = `/data/v1/${datasets[0]}?avg=${avg_fields.join())&fields=${fields.join()}&dategrain=${dategrain.join()}&filter=${filter.join()}`;

enara_martin

Thank you for your response!

I believe you mixed up ${avg_fields.join()) and ${avg_fields.join()}.

But, other than that, it works!

GrantSmith

I did. Apologies! If you could accept the answer so others can made easily find it out they have the same question I’d appreciate it.

All comments

GrantSmith

According to that documentation you should be able to supply it as a GET parameter with the value of a cvs list of fields you wish you average:

var dataAggregateBy = 'day';
var dategrain = [dataDateColumnName + ' by ' + dataAggregateBy];
var query = `/data/v1/${datasets[0]}?avg=${avg_fields.join())&fields=${fields.join()}&dategrain=${dategrain.join()}&filter=${filter.join()}`;

enara_martin

Thank you for your response!

I believe you mixed up ${avg_fields.join()) and ${avg_fields.join()}.

But, other than that, it works!

GrantSmith

I did. Apologies! If you could accept the answer so others can made easily find it out they have the same question I’d appreciate it.