Dategrain combined with aggregation

As I can read here: https://developer.domo.com/docs/dev-studio-references/data-api#aggregations
"DATEGRAIN
Perform a groupby with predefined date grains. By default, numerical columns are summed and unique entries of non-numerical columns are counted. Can be combined with an aggregation to override this default behavior."
I would like to change the default sum to an average. How could this be changed?
My query looks like this:
var dataAggregateBy = 'day'; var dategrain = [dataDateColumnName + ' by ' + dataAggregateBy]; var query = `/data/v1/${datasets[0]}?fields=${fields.join()}&dategrain=${dategrain.join()}&filter=${filter.join()}`;
Best Answers
-
According to that documentation you should be able to supply it as a GET parameter with the value of a cvs list of fields you wish you average:
var dataAggregateBy = 'day'; var dategrain = [dataDateColumnName + ' by ' + dataAggregateBy]; var query = `/data/v1/${datasets[0]}?avg=${avg_fields.join())&fields=${fields.join()}&dategrain=${dategrain.join()}&filter=${filter.join()}`;
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Thank you for your response!
I believe you mixed up
${avg_fields.join())
and${avg_fields.join()}
.But, other than that, it works!
0 -
I did. Apologies! If you could accept the answer so others can made easily find it out they have the same question I’d appreciate it.
**Was this post helpful? Click Agree or Like below**
**Did this solve your problem? Accept it as a solution!**0
Answers
-
According to that documentation you should be able to supply it as a GET parameter with the value of a cvs list of fields you wish you average:
var dataAggregateBy = 'day'; var dategrain = [dataDateColumnName + ' by ' + dataAggregateBy]; var query = `/data/v1/${datasets[0]}?avg=${avg_fields.join())&fields=${fields.join()}&dategrain=${dategrain.join()}&filter=${filter.join()}`;
**Was this post helpful? Click Agree or Like below**
**Did this solve your problem? Accept it as a solution!**0 -
Thank you for your response!
I believe you mixed up
${avg_fields.join())
and${avg_fields.join()}
.But, other than that, it works!
0 -
I did. Apologies! If you could accept the answer so others can made easily find it out they have the same question I’d appreciate it.
**Was this post helpful? Click Agree or Like below**
**Did this solve your problem? Accept it as a solution!**0
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