What is the formula to convert Julian dates (format Cyyddd) to regular date - not datetime
Best Answer
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DATE_FORMAT(`Julian`,'%Y-%m-%d')
I tested it with this data and it is working,test
is the output of the above beastmode:If I solved your problem, please select "yes" above
2
Answers
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DATE_FORMAT(`Julian`,'%Y-%m-%d')
I tested it with this data and it is working,test
is the output of the above beastmode:If I solved your problem, please select "yes" above
2 -
I assume I replace 'julian' with the julian date field name. I tried that and it did not work - Here is the error - which makes sense :
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Try it in a beastmode
If I solved your problem, please select "yes" above
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I want to do it in magic ETL2 - to work with it in my etl
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This is the formula for julian yyyyddd —- date(dateadd(day,"Julian_date"% 1000,dateadd(year,(a."Julian_date"/1000),convert(datetime,'01/01/1900')))-1)
It works in ETL2. I would assume there is something similar with the Century format
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