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M_A
M_A Member

I basically want, if an employee's attendance is marked PR PH PO PN HL HLWP HCL HEL consecutive 7 days then it should be highlighted as 1, if it is marked on the 8th day again then it should show 2 if it is marked again on the 9th day then it should give 3 and so on.

I have data like

Date

Emp ID

Attendance Status

01-05-2024

909750599

PR

01-05-2024

909777952

NM

02-05-2024

909750599

PH

02-05-2024

909777952

WO

03-05-2024

909750599

PN

03-05-2024

909777952

PR

04-05-2024

909750599

PR

04-05-2024

909777952

WO

05-05-2024

909750599

PR

05-05-2024

909777952

CI

06-05-2024

909750599

PR

06-05-2024

909777952

PR

07-05-2024

909750599

PH

07-05-2024

909777952

PH

08-05-2024

909750599

PR

08-05-2024

909777952

PR

09-05-2024

909750599

PH

09-05-2024

909777952

PH

10-05-2024

909750599

PO

10-05-2024

909777952

PO

11-05-2024

909750599

PH

11-05-2024

909777952

PH

12-05-2024

909750599

PH

12-05-2024

909777952

PH

13-05-2024

909750599

WO

13-05-2024

909777952

WO

14-05-2024

909750599

PR

14-05-2024

909777952

PR

15-05-2024

909750599

PR

15-05-2024

909777952

PR

16-05-2024

909750599

PR

16-05-2024

909777952

PR

Best Answer

  • ArborRose
    ArborRose Coach
    Answer ✓
    Options

    Using SQL, we can build the table using

    CREATE TABLE attendance (
    attendance_date DATE,
    employee_id INT,
    attendance_status VARCHAR(10)
    ); INSERT INTO attendance (attendance_date, employee_id, attendance_status) VALUES
    ('2024-05-01', 909750599, 'PR'),
    ('2024-05-01', 909777952, 'NM'),
    ('2024-05-02', 909750599, 'PH'),
    ('2024-05-02', 909777952, 'WO'),
    ('2024-05-03', 909750599, 'PN'),
    ('2024-05-03', 909777952, 'PR'),
    ('2024-05-04', 909750599, 'PR'),
    ('2024-05-04', 909777952, 'WO'),
    ('2024-05-05', 909750599, 'PR'),
    ('2024-05-05', 909777952, 'CI'),
    ('2024-05-06', 909750599, 'PR'),
    ('2024-05-06', 909777952, 'PR'),
    ('2024-05-07', 909750599, 'PH'),
    ('2024-05-07', 909777952, 'PH'),
    ('2024-05-08', 909750599, 'PR'),
    ('2024-05-08', 909777952, 'PR'),
    ('2024-05-09', 909750599, 'PH'),
    ('2024-05-09', 909777952, 'PH'),
    ('2024-05-10', 909750599, 'PO'),
    ('2024-05-10', 909777952, 'PO'),
    ('2024-05-11', 909750599, 'PH'),
    ('2024-05-11', 909777952, 'PH'),
    ('2024-05-12', 909750599, 'PH'),
    ('2024-05-12', 909777952, 'PH'),
    ('2024-05-13', 909750599, 'WO'),
    ('2024-05-13', 909777952, 'WO'),
    ('2024-05-14', 909750599, 'PR'),
    ('2024-05-14', 909777952, 'PR'),
    ('2024-05-15', 909750599, 'PR'),
    ('2024-05-15', 909777952, 'PR'),
    ('2024-05-16', 909750599, 'PR'),
    ('2024-05-16', 909777952, 'PR');

    Then we can create a query the count consecutive sequences and use that to identify the indicator.

    WITH ranked_data AS (
    SELECT
    attendance_date,
    employee_id,
    attendance_status,
    ROW_NUMBER() OVER (PARTITION BY employee_id ORDER BY attendance_date) AS seq
    FROM
    attendance
    WHERE
    attendance_status IN ('PR', 'PH', 'PO', 'PN', 'HL', 'HLWP', 'HCL', 'HEL')
    ),
    consecutive_days AS (
    SELECT
    attendance_date,
    employee_id,
    attendance_status,
    seq,
    DATEADD(DAY, -seq, attendance_date) AS grp
    FROM
    ranked_data
    ),
    highlight_counts AS (
    SELECT
    employee_id,
    attendance_date,
    attendance_status,
    seq,
    grp,
    COUNT(*) OVER (PARTITION BY employee_id, grp ORDER BY attendance_date) AS consecutive_count
    FROM
    consecutive_days
    )
    SELECT
    attendance_date,
    employee_id,
    attendance_status,consecutive_count,
    CASE
    WHEN consecutive_count >= 7 THEN (consecutive_count - 1) / 7 + 1
    ELSE 0
    END AS highlight_indicator
    FROM
    highlight_counts
    ORDER BY
    employee_id,
    attendance_date;

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Answers

  • ArborRose
    ArborRose Coach
    Answer ✓
    Options

    Using SQL, we can build the table using

    CREATE TABLE attendance (
    attendance_date DATE,
    employee_id INT,
    attendance_status VARCHAR(10)
    ); INSERT INTO attendance (attendance_date, employee_id, attendance_status) VALUES
    ('2024-05-01', 909750599, 'PR'),
    ('2024-05-01', 909777952, 'NM'),
    ('2024-05-02', 909750599, 'PH'),
    ('2024-05-02', 909777952, 'WO'),
    ('2024-05-03', 909750599, 'PN'),
    ('2024-05-03', 909777952, 'PR'),
    ('2024-05-04', 909750599, 'PR'),
    ('2024-05-04', 909777952, 'WO'),
    ('2024-05-05', 909750599, 'PR'),
    ('2024-05-05', 909777952, 'CI'),
    ('2024-05-06', 909750599, 'PR'),
    ('2024-05-06', 909777952, 'PR'),
    ('2024-05-07', 909750599, 'PH'),
    ('2024-05-07', 909777952, 'PH'),
    ('2024-05-08', 909750599, 'PR'),
    ('2024-05-08', 909777952, 'PR'),
    ('2024-05-09', 909750599, 'PH'),
    ('2024-05-09', 909777952, 'PH'),
    ('2024-05-10', 909750599, 'PO'),
    ('2024-05-10', 909777952, 'PO'),
    ('2024-05-11', 909750599, 'PH'),
    ('2024-05-11', 909777952, 'PH'),
    ('2024-05-12', 909750599, 'PH'),
    ('2024-05-12', 909777952, 'PH'),
    ('2024-05-13', 909750599, 'WO'),
    ('2024-05-13', 909777952, 'WO'),
    ('2024-05-14', 909750599, 'PR'),
    ('2024-05-14', 909777952, 'PR'),
    ('2024-05-15', 909750599, 'PR'),
    ('2024-05-15', 909777952, 'PR'),
    ('2024-05-16', 909750599, 'PR'),
    ('2024-05-16', 909777952, 'PR');

    Then we can create a query the count consecutive sequences and use that to identify the indicator.

    WITH ranked_data AS (
    SELECT
    attendance_date,
    employee_id,
    attendance_status,
    ROW_NUMBER() OVER (PARTITION BY employee_id ORDER BY attendance_date) AS seq
    FROM
    attendance
    WHERE
    attendance_status IN ('PR', 'PH', 'PO', 'PN', 'HL', 'HLWP', 'HCL', 'HEL')
    ),
    consecutive_days AS (
    SELECT
    attendance_date,
    employee_id,
    attendance_status,
    seq,
    DATEADD(DAY, -seq, attendance_date) AS grp
    FROM
    ranked_data
    ),
    highlight_counts AS (
    SELECT
    employee_id,
    attendance_date,
    attendance_status,
    seq,
    grp,
    COUNT(*) OVER (PARTITION BY employee_id, grp ORDER BY attendance_date) AS consecutive_count
    FROM
    consecutive_days
    )
    SELECT
    attendance_date,
    employee_id,
    attendance_status,consecutive_count,
    CASE
    WHEN consecutive_count >= 7 THEN (consecutive_count - 1) / 7 + 1
    ELSE 0
    END AS highlight_indicator
    FROM
    highlight_counts
    ORDER BY
    employee_id,
    attendance_date;

    ** Was this post helpful? Click Agree or Like below. **
    ** Did this solve your problem? Accept it as a solution! **