Magic ETL Regex

I have a column in my dataset that contains strings of text, similar to the following:
Campaign 225 - Facebook - CampaignName.(ThankYou) 4-225_CampaignName
Google Ad - Franchise: Service.(ThankYou) 1-G-Fran_Service
Campaign 225 - Google - I: CampaignName: AdGroupName.(ThankYou) 3-G-225_PT_WFH
I want to use the "Replace Text" function to eliminate all text before the bolded text above.
Any ideas?
Best Answer
-
I solved this on my own using the greedy quantifier, in case anyone has the same question. It got me all the way up to the space before the string of interest.
.+(?=[ ]\S)
0
Answers
-
I solved this on my own using the greedy quantifier, in case anyone has the same question. It got me all the way up to the space before the string of interest.
.+(?=[ ]\S)
0 -
Wondering if I could get here. I'm trying to do something similar. I just want Blank Entries to be replaced to "General"
I tried various combinations:- \s
- ^\s*$
- ^$
All to no avail!
Halp Please?
Much appreciated!0
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