Active users last x days
I have the following dataset ( see the attached screenshot). It shows the userID active on a given date and the session time. I want to determine which users were active in the current week, t-1 week, t-2 week etc. As an output I want a table with the following columns: UserID, active this week column ( 0 or 1 value), active last week (0 or 1 value) etc. How can I transform my current dataset in ETL or create calculated fields to create such an output. Any help would be greatly appreciated!
Best Answer
-
If you were to use a SQL transform it would look something like this:
SELECT `User ID`,
CASE WHEN SUM(CASE WHEN Week(`Date`) = Week(Curdate())
AND Year(`Date`) = Year(Curdate())
THEN 1
ELSE 0
END) >= 1 THEN 1 ELSE 0 END AS 'Current Week',
CASE WHEN SUM(CASE WHEN Week(`Date`) = Week(DATE_SUB(Curdate(), INTERVAL 1 Week))
AND Year(`Date`) = Year(DATE_SUB(Curdate(), INTERVAL 1 Week))
THEN 1
ELSE 0
END) >= 1 THEN 1 ELSE 0 END AS 'Last Week'
FROM dataset
GROUP BY `User ID`That should give you the Userid, CurrentWeek and LastWeek columns. If you need additional, just modify the Date_Sub Intervals for the Last Week example.
Hope this helps,
ValiantSpur
**Please mark "Accept as Solution" if this post solves your problem
**Say "Thanks" by clicking the "heart" in the post that helped you.1
Answers
-
If you were to use a SQL transform it would look something like this:
SELECT `User ID`,
CASE WHEN SUM(CASE WHEN Week(`Date`) = Week(Curdate())
AND Year(`Date`) = Year(Curdate())
THEN 1
ELSE 0
END) >= 1 THEN 1 ELSE 0 END AS 'Current Week',
CASE WHEN SUM(CASE WHEN Week(`Date`) = Week(DATE_SUB(Curdate(), INTERVAL 1 Week))
AND Year(`Date`) = Year(DATE_SUB(Curdate(), INTERVAL 1 Week))
THEN 1
ELSE 0
END) >= 1 THEN 1 ELSE 0 END AS 'Last Week'
FROM dataset
GROUP BY `User ID`That should give you the Userid, CurrentWeek and LastWeek columns. If you need additional, just modify the Date_Sub Intervals for the Last Week example.
Hope this helps,
ValiantSpur
**Please mark "Accept as Solution" if this post solves your problem
**Say "Thanks" by clicking the "heart" in the post that helped you.1 -
Perfect! It worked. Thank you!
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