I am replacing power BI DAX formula into Beast Mode

Arjuman

CALCULATE(DIVIDE([SumOfTimeToClosed],[ResolvedCountForMeter]), 
    FILTER(JiraBugsTable, YEAR(JiraBugsTable[ResolvedDate]) = [CurrentYear]))


Sumoftimetoclosed and ResolvedcountforMeter details below

SumOfTimeToClosed = CALCULATE(SUM(JiraBugsTable[DaysToResolution]),FILTER(JiraBugsTable, YEAR(JiraBugsTable[ResolvedDate]) = [CurrentYear]))
ResolvedCountForMeter = COUNTX( FILTER(JiraBugsTable, JiraBugsTable[isBugResolved] = 1), JiraBugsTable[JiraKey])

In DOMO I have written this but it isn't working

(CASE when YEAR(`ResolvedDate`) = YEAR(CURRENT_DATE()) then SUM((CASE when YEAR(`ResolvedDate`) = YEAR(CURRENT_DATE()) then `DaysToResolution` else 0 end)) / COUNT(DISTINCT (CASE when `isBugResolved`= 1 then `JiraKey`else 0 end)) end) 

Godiepi

Hi @Arjuman ,

Try this below, you might need to add a condition to adjust when dividing by 0

SUM(CASE
        WHEN YEAR(`ResolvedDate`) = YEAR(CURRENT_DATE ())
            THEN `DaysToResolution`
        ELSE 0
    END)
    /
COUNT(DISTINCT
        CASE
            WHEN YEAR(`ResolvedDate`) = YEAR(CURRENT_DATE ())
            AND `isBugResolved` = 1
                THEN `JiraKey`
            ELSE 0
        END)

jaeW_at_Onyx

@Arjuman in addition to posting raw code, it might be beneficial to describe what you're trying to accomplish and let the community know what shape your table is in.

it'll certainly help in cases when your SQL is bugged and you're looking for support trying to make it work.

(CASE when YEAR(`ResolvedDate`) = YEAR(CURRENT_DATE()) then SUM((CASE when YEAR(`ResolvedDate`) = YEAR(CURRENT_DATE()) then `DaysToResolution` else 0 end)) / COUNT(DISTINCT (CASE when `isBugResolved`= 1 then `JiraKey`else 0 end)) end)

in any case, you generally can't put an aggregate function, SUM, inside a CASE statement.

in @Godiepi 's response you'll notice all the aggregates are outside.

keep in mind 0 =!= NULL.

if you do a COUNT (DISTINCT case when ... else 0 end ) you'll include 0 as one of your counts.

ex. count(distinct of [a, b, 0 , 0] would be 3. That may or not be appropriate.

whereas count(distinct [a,b, null,null] would be 2.