% of Total Using Distinct Count
I need to show a % Total of Accounts in the below card. I used the following to get the below % of Total accounts. However, there are multiple rows per account name. The # of Accounts column is calculating a Distinct Count, but the % of Total appears to be calculating of the # of rows, not a distinct count of the Account Name.
SUM(SUM(1)) OVER (PARTITION BY `Status`) / SUM(SUM(1)) OVER ()
Is there a way to show # of distinct accounts per status / total # of unique accounts?
Try SUM(COUNT(DISTINCT `Account Name`))**Was this post helpful? Click Agree or Like below**
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you can't do a count(distinct) across rows in a table card. if you take the sum of count(distinct) it assumes that an account does not exist across multiple statuses.
unfortunately, you cannot count(count(distinct)) b/c the number of accounts would have already been aggregated.
instead you could UNION a set of rows containing STATUS = 'Unique Accounts' with one row per account to the dataset.Jae Wilson
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I ran into a similar problem where...
I was also trying to calculate % of Total Unique Records but kept getting % of Total Records when I set up the calculation as
COUNT(DISTINCT 'id field') / COUNT(DISTINCT 'id field') FIXED()
I did what @jaeW_at_Onyx suggested (or at least a version of it), where I identified the first instance of all "duplicates" in the dataset and tag it as "unique" in an identifier column so that I can set the denominator to count values in this unique identifier column instead.
To set up this unique identifier column I used Rank & Window to get the Row Number partitioned on the field where the unique ID is supposed to be (in my case Tracking Number).
Once I have the column that identifies just the first instance of all duplicate rows, I set the calculation to be
COUNT(DISTINCT 'id field') / COUNT('unique record') FIXED (), and it worked!0
Here's an example Magic ETL that does this:
This creates a column that has the Total # Accounts on every row
You can then use the average of that as your denominator in the BeastMode:
COUNT(DISTINCT `Account Number`)/avg(`Total # Accounts`)0
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