If contains statement beast mode
I essentially have a list of URLs in one column and need to extract out the advertiser into a new column. I want to use an if contains statement to search every row in data set and see if it holds the pertaining advertiser name. Below is what I what both columns to look like and the code that I tried.
COL.a COL.b
url Advertiser name
CASE
WHEN `Page` LIKE '%adCREASIANs%' THEN 'By Gina'
WHEN `Page` LIKE '%Aerovex SystemsInc%' THEN 'Hemp Beauty'
ELSE 'NA'
END;
Best Answer
-
remove the ; at the end of the syntax
case when `url` like '%goo%' then 'google'
when `url` like '%adCREASIANs%' THEN 'By Gina'
when `url` like '%Aerovex SystemsInc%' THEN 'Hemp Beauty'
else 'na' end
2
Answers
-
remove the ; at the end of the syntax
case when `url` like '%goo%' then 'google'
when `url` like '%adCREASIANs%' THEN 'By Gina'
when `url` like '%Aerovex SystemsInc%' THEN 'Hemp Beauty'
else 'na' end
2
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