Field that returns 1/0 based on all similar values in the same column
Hello,
This should be pretty simple but I can't find the solution. I tried fiddling around in ETL and beastmode, as well as googling, but was unsuccessful.
Here is the problem:
I am trying to create a column that returns 1 when any unique Job has a PO#. For example, in the second row there is no PO, however the 1st row is also Job 1 and has a PO. So I want row 2 to return 1.
Job | PO # | Goal |
1 | 123 | 1 |
1 | 1 | |
2 | 124 | 1 |
2 | 125 | 1 |
3 | 0 | |
3 | 0 | |
3 | 0 |
Thank you in advance for your help.
Comments
-
If you are creating a table card, and you have it sorted by `Job` then you should be able to get something like this to accomplish what you are looking for:
COUNT(DISTINCT `PO #`) OVER (PARTITION BY `Job`)
However, if you sort your table by something else, then this beastmode will break
0 -
Hi there, I tried your method and unfortunately I did not manage to make it work.
However, I copied the idea by doing a rank & window in the dataflow, with a function count of PO's and partitioned by Job's. It is a bit of patchwork as it was mandatory that I had a "frame range" (which I would rather not have) but other than that, it has worked.
Thank you
1 -
You could keep it unbounded in a redshift dataflow
0
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