Comments
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Ah I figured it out. It wanted a % at the start of the string as well - so case when DP Response 2 LIKE ‘%DP: Sorry%’ then User Question 2 end Thanks so much for your help!
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@MichelleH that did help with the syntax error, but somehow I'm getting no data returned with that formula as a whole. Do you know if I'm missing something that would actually pull through the value of the “User Question 2” column?