Using RegEx to Extract Date
Hi all!
I am looking for advice on extracting a Maturity Date from a column containing a string of text, example:
string: 12months,MATURITY DATE:23-Jun-2022,BALANCE;$12345,PRODUCT
Return: 23-Jun-2022
I am able to successfully select the date by using: \d{2}-[A-z]{3}-\d{4}
But am unable to replace this so that it only returns the date. I always end up just getting the full text string.
Thanks in advance!
Best Answer
-
Try this:
REGEXP_REPLACE(`string`, '^.*(\d{2}-[A-z]{3}-\d{4}).*$', '$1')
You need to replace the entire string not just the substring. This is why there's ^.* and .*$ to match anything before and after the date value respectively.
**Was this post helpful? Click Agree or Like below**
**Did this solve your problem? Accept it as a solution!**2
Answers
-
Try this:
REGEXP_REPLACE(`string`, '^.*(\d{2}-[A-z]{3}-\d{4}).*$', '$1')
You need to replace the entire string not just the substring. This is why there's ^.* and .*$ to match anything before and after the date value respectively.
**Was this post helpful? Click Agree or Like below**
**Did this solve your problem? Accept it as a solution!**2 -
Thank you @GrantSmith, worked perfectly. I appreciate it!
0
Categories
- All Categories
- 1.4K Product Ideas
- 1.4K Ideas Exchange
- 1.4K Connect
- 1.2K Connectors
- 284 Workbench
- 4 Cloud Amplifier
- 4 Federated
- 2.9K Transform
- 88 SQL DataFlows
- 554 Datasets
- 2.2K Magic ETL
- 3.3K Visualize
- 2.3K Charting
- 563 Beast Mode
- 9 App Studio
- 27 Variables
- 577 Automate
- 140 Apps
- 414 APIs & Domo Developer
- 22 Workflows
- 1 DomoAI
- 28 Predict
- 12 Jupyter Workspaces
- 16 R & Python Tiles
- 350 Distribute
- 90 Domo Everywhere
- 258 Scheduled Reports
- 2 Software Integrations
- 91 Manage
- 88 Governance & Security
- 9 Product Release Questions
- Community Forums
- 42 Getting Started
- 28 Community Member Introductions
- 85 Community Announcements
- 4.8K Archive